Talk:Pareto efficiency/Archive 2
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Archive 1 | Archive 2 |
GRAPH IS WRONG
Something's wrong with this graph, right? Only ONE point on the frontier is Pareto efficient. E.g.: Suppose your production is totally focused on the production of A and you produce 0 B. Yet all your citizens prefer B to A. Obviously moving production toward B is a PE move. — Preceding unsigned comment added by 141.161.133.5 (talk) 20:21, 18 July 2017 (UTC)
There is something wrong with the plot, but I don't think it's what the user stated above. There can be infinitely many points on the Pareto front, so long as each point is not dominated by another, i.e. you cannot improve all the objective simultaneously. The user's point about population preferences speaks to weighting the objectives and is one method to select the preferred solution from among the set of Pareto optimal solutions. There is however a problem with the plot. As shown, State N is Pareto optimal. It dominates states A-D in terms of Item 1, and dominates states E-H in terms of Item 2. State N is therefore a non-dominated (or non-inferior) solution and is part of the Pareto front.
Gcranston (talk) 19:36, 5 September 2017 (UTC)
- There is nothing wrong with the plot. I thought so too, but if you read the caption, it describes the image as "a Pareto-efficient frontier, where the frontier and the area left and below it is a continuous room of choices." So, the points in the image are not the only possible points, but rather examples of points in the space. N is not optimal, because there is a point on the line between D and E that has more of item 1 and of item 2. The image is fine, and should not be changed Mattster3517 (talk) 18:44, 1 January 2018 (UTC)
4.16.194.230 (talk) 22:49, 19 December 2018 (UTC) If is N not on the frontier, but then in the other plot the points immediately left of A and right of B are on the the frontier, what's going on? Doesn't seem that both plots can be right. My $0.02 is that point N in the first plot is not dominated by neighboring points and should be on the frontier.
The graph is wrong. It is true that N & K are not PE. But A-H are only POSSIBLY PE. This depends on the MRSs of consumers. As the first person, above, said: If consumers have no taste at all for good 2, then obviously point A is not PE. — Preceding unsigned comment added by 73.163.185.230 (talk) 17:49, 21 April 2018 (UTC)
If is N not on the frontier, but then in the other plot the points immediately left of A and right of B are on the the frontier, what's going on? Doesn't seem that both plots can be right. My $0.02 is that point N in the first plot is not dominated by neighboring points and should be on the frontier. 4.16.194.230 (talk) 22:49, 19 December 2018 (UTC)
- Please note: comments generally should be added at the bottom of a discussion. And should be signed by adding the "four tildes" ("~~~~") at the end of your comment. Also: discussions of what is "right" (or wrong) generally require reference(s) to a source. ♦ J. Johnson (JJ) (talk) 00:20, 20 December 2018 (UTC)
- The graph in question is the production possibilities frontier, and hence is not about preferences but rather is about possible combinations of products produced. I’ve moved the graph to a more appropriate section to avoid confusion. Loraof (talk) 18:31, 4 January 2019 (UTC)